0=-16x^2+80x+2

Solution for 0=-16x^2+80x+2 equation:

0=-16x^2+80x+2

We move all terms to the left:

0-(-16x^2+80x+2)=0

We add all the numbers together, and all the variables

-(-16x^2+80x+2)=0

We get rid of parentheses

16x^2-80x-2=0

a = 16; b = -80; c = -2;
Δ = b2-4ac
Δ = -802-4·16·(-2)
Δ = 6528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6528}=\sqrt{64*102}=\sqrt{64}*\sqrt{102}=8\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-8\sqrt{102}}{2*16}=\frac{80-8\sqrt{102}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+8\sqrt{102}}{2*16}=\frac{80+8\sqrt{102}}{32}
$